Answer:
The answer is "[tex]\bold{186 \times \varepsilon \ 10^9}[/tex]".
Explanation:
Given value:
[tex]\to n= 10 \% \\\\[/tex]
[tex]= 0.10\\[/tex]
[tex]\text{From the properties of 1020 steel:}\\\\\to yield \ power (\sigma \ y) = 350 \ MPa\\\\[/tex]
[tex]= 350 \times 10^6 \ \frac{N}{m^2}\\\\[/tex]
[tex]\to elasticity(E) \ Modulus = 186 \ GPa[/tex]
[tex]= 186 \times 10^9 \ \frac{N}{m^e}\\\\[/tex]
Strength must be improved by pressure: [tex]\varepsilon[/tex]
[tex]\to \sigma = E \times \varepsilon[/tex]
[tex]= 186 \times \varepsilon \times 10^9\\\\= 186 \ \varepsilon \times 10^9[/tex]
