Answer:
Velocity = 39.11 m/s
Explanation:
Applying the third equation of motion:
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2gh
where V is the final velocity of the baseball, U is its initial velocity, g is the force of gravity and h is the height.
Thus, U = 0, g = 9.8 m/[tex]s^{2}[/tex] and h = 256 ft
But, 1 ft = 0.3048 m
So that;
h = 256 feet = 78.0288 meters
[tex]V^{2}[/tex] = 2 x 9.8 x 78.0288
= [tex]\sqrt{1529.37}[/tex]
V = 39.11 m/s
The velocity of the baseball is 39.11 m/s.
