Answer:
1. Molecular equation
BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
2. Complete Ionic equation
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)
3. Net ionic equation
Cl¯(aq) + Ag⁺(aq) —> AgCl(s)
Explanation:
1. Molecular equation:
BaCl2(aq) + AgNO3(aq) –> AgCl(s) + Ba(NO3)2 (aq)
The above equation can be balance as follow:
There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front of AgCl as shown below:
BaCl2(aq) + AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
There are 2 atoms of Ag on the right side and 1 atom on the left side. It can be balance by putting 2 in front of AgNO3 as shown below:
BaCl2(aq) + 2AgNO3(aq) –> 2AgCl(s) + Ba(NO3)2 (aq)
Now, the equation is balanced
2. Complete ionic equation
In solution, BaCl2 and AgNO3 will dissociate as follow:
BaCl2(aq) —> Ba²⁺(aq) + 2Cl¯(aq)
AgNO3(aq) —> Ag⁺(aq) + NO3¯ (aq)
BaCl2(aq) + AgNO3(aq) –>
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯
3. Net ionic equation
Ba²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO3¯ (aq) —> 2AgCl(s) + Ba²⁺(aq) + 2NO3¯(aq)
Cancel out the spectator ions i.e ions that appears on both side of the equation in order to get the net ionic equation. This is illustrated below:
2Cl¯(aq) + 2Ag⁺(aq) —> 2AgCl(s)
Cl¯(aq) + Ag⁺(aq) —> AgCl(s)
