Answer:
The average power dissipated by the resistance is 144.5 W.
Explanation:
Given;
peak current of the AC = I₀ = 1.7 A
resistance, R = 100 ohm
The root mean square current is given by;
[tex]I_{rms} = 0.7071 \ I_o\\\\I_{rms} = 0.7071 * 1.7\\\\I_{rms} = 1.2021 \ A[/tex]
The average power dissipated by the resistance is given by;
[tex]P_{avg} = I_{rms}^2R\\\\P_{avg} = (1.2021)^2(100)\\\\P_{avg} =144.5 \ W[/tex]
Therefore, the average power dissipated by the resistance is 144.5 W.
