Complete Question
A block with a mass of 34.0 kg is pushed with a horizontal force of 150 N. The block moves at a constant speed across a level, rough surface a distance of 6.95 m.
(a) What is the work done (in J) by the 150 N force
b) find the coefficient of kinetic friction between the crate and rough surface
Answer:
a
[tex]W = 1042.5 \ J [/tex]
b
[tex] \mu_k = 0.45 [/tex]
Explanation:
From the question we are told that
The mass of the block is [tex]m = 34.0 \ kg[/tex]
The horizontal force is [tex]F = 150 \ N[/tex]
The distance moved is [tex]d = 6.95 \ m[/tex]
Generally the work done is mathematically represented as
[tex]W = F * d[/tex]
=> [tex]W = 150 * 6.95 [/tex]
=> [tex]W = 1042.5 \ J [/tex]
Generally the net force acting on the block is
[tex]F_{net} = F - m * g * \mu_k[/tex]
=> Here [tex]F_{net} = m * a[/tex]
Here a is the acceleration and the value is zero because velocity is constant
So
[tex]F_{net} = 34.0 * 0[/tex]
So
[tex] \mu_k = 0.45 [/tex]
