Answer:
A. -6
Step-by-step explanation:
The slope of the line that is perpendicular to the graph y = ⅙x + 8, is a negative reciprocal of the slope of the graph, y = ⅙x + 8.
What this means is that, if you multiply the slope of y = ⅙x + 8, and the slope of the line perpendicular to it, you would have -1. That is [tex] m_1 * m_2 = -1 [/tex].
Where,
[tex] m_1 [/tex] = slope of y = ⅙x + 8.
[tex] m_2 [/tex] = slope of the line perdendicular to y = ⅙x + 8.
The slope of y = ⅙x + 8 is ⅙.
Substitute [tex] m_1 [/tex] = ⅙ into [tex] m_1 * m_2 = -1 [/tex], to find the slope [tex] (m_2) [/tex] of the line that is perpendicular to the graph of y = ⅙x + 8.
[tex] \frac{1}{6} * m_2 = -1 [/tex]
Multiply both sides by 6
[tex] \frac{1}{6} * m_2 * 6 = -1*6 [/tex]
[tex] 1*m_2 = -6 [/tex]
[tex] m_2 = -6 [/tex]
The slope of the line that is perpendicular to the graph of y = ⅙x + 8 is -6.
