The temperature of water in a container was 60 degrees Celsius. Ten minutes later, the water temperature was 35 degrees Celsius. What was the rate of cooling of the water?

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aethan
60 degree 35 degree i dint know

The rate of cooling of the water, whose temperature decreases from 60 °C to 35 °C in 10 minutes, is -2.5 ° C/min.

Initially, we have water at 60 °C. After 10 minutes, its temperature decreases to 35 °C. The rate of cooling of the water is equal to the change in its temperature over the elapsed time.

[tex]r = \frac{35 \° C - 60 \° C }{10 min} = -2.5 \° C/min[/tex]

The rate of cooling of the water, whose temperature decreases from 60 °C to 35 °C in 10 minutes, is -2.5 ° C/min. That is, its temperature decreases by 2.5 °C every minute.

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