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A cannon is fired horizontally from the edge of a small cliff. The height of the cliff is 104.0 m. The cannon ball is fired with a perfectly horizontal velocity of 24.6 m/s and it took 2.3s to reach the ground. How far will the cannon ball fly horizontally before it strikes the ground?

Respuesta :

Answer:

h = 134.65 m

Explanation:

It is given that,

The height of the cliff is 104.0 m, h₀ = 104 m

Initial horizontal velocity of the ball, u = 24.6 m/s

It takes 2.3 s to reach the ground, t = 2.3 s

We need to find how far will the cannon ball fly horizontally before it strikes the ground. let it is h. Using second equation of motion as follows :

[tex]h=h_0+ut+\dfrac{1}{2}at^2[/tex]

Here, a = -g

So,

[tex]h=h_0+ut-\dfrac{1}{2}gt^2\\\\h=104+24.6(2.3)-\dfrac{1}{2}\times 9.8\times (2.3)^2\\\\h=134.65\ m[/tex]

So, the cannonball will cover a distance of 134.65 m before it strikes the ground.

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