The slope-intercept form of the equation of a line that passes through point (–3, 10) is y = 2x + 16. What is the point-slope form of the equation for this line?
the equation would be D bc using the point given u can fill out the equation y-y1=m(x-x1) so it would be y-10=m(x-(-3). then fill in slope and change the (x-(-3) into x+3. The equation is now y-10=2(x+3).