Answer:
The acceleration of the block is -0.884 m/s²
Explanation:
Given;
mass of the block, m = 43 kg
frictional force, Fk = 61 N
applied force on object, F = 23 N
The net horizontal force on the body is given by;
∑Fx = F - Fk
∑Fx = 23 N - 61 N
∑Fx = -38 N
Apply Newton's second law of motion;
F = ma
a = F/m
a = -38 / 43
a = -0.884 m/s²
this is the deceleration of the block, because the applied the applied force is than the frictional force; which is preventing forward motion of the block.
Therefore, the acceleration of the block is -0.884 m/s²
