Answer: Plz mark me brainlest
Step-by-step explanation:
You can factor out a 2, so do that first
2(x^2 - 13x + 30) = 0
Now look at x^2 - 13x + 30. Since you have a positive last term and a negative middle term, then you're looking for something in the form of (x - ?)(x - ?). We have to find two numbers whose product is 30 and whose sum is 13. The numbers must be 10 and 3:
2(x-3)(x-10) = 0