Answer:
x = 157.85 m
Explanation:
Given that,
Speed of car in horizontal direction, v = 35 m/s
Height of the cliff is 100 m
Let t is the time taken by the car to hit the ground. It can be calculated using second equation of motion which is :
[tex]s=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 and a = g
[tex]s=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2s}{g}} \\\\t=\sqrt{\dfrac{2(100)}{9.8}} \\\\t=4.51\ s[/tex]
Let x is the distance. So,
[tex]x=vt\\\\x=35\ m/s\times 4.51\ s\\\\x=157.85\ m[/tex]
So, it will cover a distance of 157.85 m.
