Answer:
7.716 (with margin: 0.001)
Step-by-step explanation:
speed = distance ÷ time
For speed to be at a minimim you need distancemin ÷ timemax
Min distance = 345 - 0.5 = 344.5m
Max Time = 44.6 + 0.05 = 44.65 sec
speedmin=344.5 ÷ 44.65 = 7.7155..... = 7.716 m/s (3 dp)
The slowest speed possible of the athlete is required.
The minimum possible speed of the runner is 7.7 m/s.
d = Distance run by the athlete = 345 meters
t = Time taken by the athlete to cover the distance = 44.6 seconds
Speed is given by
[tex]s=\dfrac{d}{t}[/tex]
[tex]s=\dfrac{345}{44.6}[/tex]
[tex]s=7.735\approx 7.7 \text{m/s}[/tex]
The speed of the athlete should be at least 7.7 m/s any less than that and the athlete will not be able to cover the required distance in the given time.
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