Answer:
The concentration of KOH solution is 17.009 moles/litre or 17.009M .
Explanation:
Here , the given reaction is -
[tex]2KOH +H_{2}SO_{4}$\rightarrow$K_{2}SO_{4}+2H_{2}O[/tex]
2moles of KOH requires 1mole for complete neutralisation.
Therefore ,
2 x number of moles of KOH = 1 x number of moles of [tex]H_{2}SO_{4}[/tex]
2 x (molarity of KOH x volume of KOH) = (Molarity of [tex]H_{2}SO_{4}[/tex] x volume of
[tex]H_{2}SO_{4}[/tex])
1 mole of [tex]OH^- $\rightarrow$[/tex] 1mole of [tex]H^+[/tex]
Molarity (KOH) = concentration (c)
volume (KOH) =15.05ML
Molarity ([tex]H_{2}SO_{4}[/tex] ) = 5.0 M
Volume of ( [tex]H_{2}SO_{4}[/tex] ) = 25.6ML
[tex]\frac{1\times(C \times15.05ml)}{OH^-} = \frac{(2\times 25.6 \times 5)}{H^+}[/tex]
C = [tex]\frac{0.2\times25.6\times5}{15.05}[/tex]
C= 17.009 moles/litre
Hence , the concentration of KOH solution is 17.009 M or moles/litre .
