The total amount of coins is 46 coins
Let x represent the number of quarters, y represent the number of dimes and z represent the number of pennies.
Each quarter is worth $0.25, each dime is worth $0.1 and each penny is worth $0.01
Since Victor has three times fewer pennies than dimes, hence:
y = 3z
y - 3z = 0 (1)
Victor also has 4 fewer quarters than pennies, hence:
x = z - 4
x - z = -4 (2)
The total worth of the coin is $4.60, therefore:
0.25x + 0.1y + 0.01z = 4.60 (3)
Solving equations 1, 2 and 3 simultaneously gives:
x = 6, y = 30, z = 10
Total coins = 6 + 30 + 10 = 46
Therefore there are 6 quarters, 30 dimes and 10 pennies
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