Respuesta :
Answer:
2 Sb3+ (aq) + 3 S2- (aq) ⇒ Sb2S3 (s)
Explanation:
Molecular equation for Sb(OH)3 + Na2S
2 Sb(OH)3 (aq) + 3 Na2S (aq) ⇒ Sb2S3 (s) + 6 NaOH (aq)
Ionic equation for Sb(OH)3 + Na2S
2 Sb3+ + 6 OH- + 6 Na+ + 3 S2- ⇒ Sb2S3 + 6 Na+ + 6 OH-
To get the net ionic, any duplications on the left or right side would be canceled.
∴ Thus, the net ionic equation for Sb(OH)3 + Na2S is 2 Sb3+ (aq) + 3 S2- (aq) ⇒ Sb2S3 (s)
The net ionic equation is a chemical equation that shows only those ions that are involved directly in the formation of the final product. The net ionic equation for the given reaction is [tex]\bold { 2 Sb3^+ (aq) + 3 S_2^- (aq) \rightarrow Sb_2S_3 (s)}[/tex].
Net ionic equation:
It is a chemical equation that shows only those ions that are involved directly in the formation of the final product.
So, molecular equation,
[tex]\bold {2 Sb(OH)_3 (aq) + 3 Na_2S (aq) \rightarrow Sb_2S_3 (s) + 6 NaOH (aq)}[/tex]
Now, write the ionic equation,
[tex]\bold {2 Sb_3^+ + 6 OH^- + 6 Na+ + 3 S_2^- \rightarrow Sb_2S_3 + 6 Na^+ + 6 OH^-}[/tex]
To make a Net ionic equation cancel all the duplicate ions present on both sides of the equation.
[tex]\bold { 2 Sb3^+ (aq) + 3 S_2^- (aq) \rightarrow Sb_2S_3 (s)}[/tex]
Therefore, the net ionic equation for the given reaction is [tex]\bold { 2 Sb3^+ (aq) + 3 S_2^- (aq) \rightarrow Sb_2S_3 (s)}[/tex].
Learn more about the Net ionic equation:
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