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2. A motorcycle starts at rest and moves a distance of 350 m. If it has a constant acceleration of 4.55m/s2, what is
its final velocity?

Respuesta :

Answer:

Vf = ≈56.436 m/s

Explanation:

We'll need to use the equation:

Vf^2 = Vi^2 + 2aΔx

Plugging in what we know, we get:

Vf^2 = (0)^2 + 2(4.55)(350)

Finally, some algebra:

Vf^2 = 3185

Vf = ≈56.436

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