contestada

A machine at a food-distribution factory fills boxes of rice. The distribution of the weights of filled boxes of rice has
an approximately Normal distribution, with a mean of 28.2 ounces and a standard deviation of 0.4 ounces Boxes
are often weighed before shipping, and any box with a weight of at most 27.5 ounces is considered underweight
and is rejected for distribution. What percentage of filled boxes of rice are rejected for distribution?
Find the z-table here.
04.0%
24.2%
75.8%
96.0%

Respuesta :

edelweissfiore6

Answer:

24.2%

Step-by-step explanation:

Ver imagen edelweissfiore6

4% of boxes are diallowed for distribution.

What is Normal Probability Distribution?

The z-score of a measure X  with mean μ and standard deviation σ  is given by:

Z=(X-μ)/σ

The z-score measures the number of standard deviations where the measure is up or below of the mean.

According to the asked problem,

Box of weight<27.5 will be considered as underweight and will be calculated as rejected piece.

Here in the problem μ=28.2

σ= 0.4

So, p(X<27.5)

=P((X-μ)/σ <(27.5-28.2)/0.4)

=P(Z<-1.75)

=1-P(Z<1.75)

=1-P(1.75)

=1-0.9599

=0.0401

=4.0%

Therefore 4% of boxes are diallowed for distribution.

Learn more about Normal Probability Distribution

Here: https://brainly.com/question/17009495

#SPJ2

Otras preguntas