Let's solve for x
9(2x+1) < 9x - 18
18x+9 < 9x-18
18x-9x < -18-9
9x < -27
x < -27/9
x < -3
Any value smaller than -3 is in the solution set
That means we have {-4, -5, -6, ...} as our solution set if x was only allowed to be an integer.
We can rule out choices B through D because of this. Only choice A remains, which I'm assuming you meant to say -4 instead of simply 4. If choice A says -4, then this is the answer.
If it doesn't say -4, then that isn't the answer and none of the answer choices work.
Note: if your original inequality is [tex]9(2x+1) \le 9x-18[/tex] then it solves to [tex]x \le -3[/tex] allowing x = -3 to be part of the solution set now. If you have an "or equal to" then that means B) -3 is the answer.
It seems like there might be a typo somewhere so I would double check.
