How many oxygen molecules are present in 113.97 liters of oxygen gas at STP?
A
6.8601 x 1025
OB.
6.8601 X 1024
C.
3.064 x 1024
D.
3.064 x 1023
E.
6.8601 x 1014

Respuesta :

The answer will be D :)
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The number of oxygen molecules exists present in 113.97 liters of oxygen gas at STP is [tex]$ 30.64 * 10^{23}[/tex].

What is Avogadro's law?

Avogadro's law exists as an experimental gas law describing the volume of a gas to the quantity of substance of gas present.

According to Avogadro's law, 1 mole of every substance occupies 22.4 Liters at standard temperature and pressure and contains Avogadro's number of particles.

22.4 L of oxygen gas ([tex]O_{2}[/tex]) contains = [tex]$6.02*10^{23}[/tex] molecules of oxygen

113.97 L of oxygen gas ([tex]O_{2}[/tex]) contains = [tex]$(6.02*10^{23} /22.4 L)*113.97L[/tex]

[tex]$= 30.64 * 10^{23}[/tex] molecules of oxygen

Therefore, the correct answer is option D.[tex]$ 30.64 * 10^{23}[/tex].

To learn more about Avogadro's law refer to:

https://brainly.com/question/2928278

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