Answer:
8
Step-by-step explanation:
[tex]2x-5\leq 11\\2x\leq 16\\x\leq 8[/tex]
[tex]-2x+7\leq -9\\-2x\leq -16\\x\geq 8[/tex]
Once [tex]x \in \mathbb{Z}[/tex] we can conclude that
[tex]A=(-\infty, 8][/tex]
[tex]B=[8, \infty)[/tex]
So [tex]A\cap B = 8[/tex]