Answer:
The answer is Enolase.
Explanation:
The reason why is because "Fluoride inhibits enolase, which is far downstream in the glycolytic pathway. Enzymes upstream of enolase remain active and continue to metabolize glucose until substrates are exhausted."
Fluoride is an inhibitor of enzyme enolase. Thus, the correct option is E.
Glycolysis may be defined as a process that involves the partial breakdown of glucose into pyruvate, a three-carbon compound by cells with the utilization of 10 sequential enzymes. It is also known as the Embeden-Meyerhoff pathway.
Fluoride functions primarily by inhibiting the enzyme enolase in the glycolytic pathway. This is because enzymes present in the upstream of enolase remain active and continue to metabolize glucose until substrates are consumed. This inhibition of the specific enzyme occurs in the presence of inorganic phosphate.
The enzyme enolase is responsible for the reversible conversion of phosphoglycerate to phosphoenolpyruvate and vice versa in the glycolysis pathway. It is present in the downstream part of the glycolysis process.
Therefore, Fluoride is an inhibitor of enzyme enolase. Thus, the correct option is E.
To learn more about Glycolysis, refer to the link:
https://brainly.com/question/737320
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