Answer:
Step-by-step explanation:
(x+2)²+5=0
[tex]x^{2} +4+5 = 0[/tex]
[tex]x^{2} +9 = 0[/tex]
[tex]x^{2} = -9[/tex]
x= no solution
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We know that the square of any number is greater or equal to zero Thus ;
[tex] ({x + 2})^{2} \geqslant 0[/tex]
And ;
[tex]5 > 0[/tex]
Sum of the two positive numbers never equal zero Thus there isn't any value for x
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