Respuesta :
So we need to write some expressions first.
So for 2 consecutive odd integers you could have (2n-1) and (2n+1) as these are consecutive and odd. When you multiply these you get 2915 so
(2n-1)(2n+1) = 2915
So multiply out
4n^2 -2n +2n -1 = 2915
4n^2 -1 = 2915
4n^2 = 2916
n^2 = 729
N = 27
So 2n + 1 is 27x2 +1 is 55 and 2n -1 is 53
The two integers are 55 and 53
Hope this helps, let me know if you have any questions
So for 2 consecutive odd integers you could have (2n-1) and (2n+1) as these are consecutive and odd. When you multiply these you get 2915 so
(2n-1)(2n+1) = 2915
So multiply out
4n^2 -2n +2n -1 = 2915
4n^2 -1 = 2915
4n^2 = 2916
n^2 = 729
N = 27
So 2n + 1 is 27x2 +1 is 55 and 2n -1 is 53
The two integers are 55 and 53
Hope this helps, let me know if you have any questions
The values of the two consecutive odd integers are 53 and 55.
Let the two consecutive odd integers be x and x+2.
Based on the information given, the equation to solve the question will be:
x(x + 2) = 2915
x² + 2x = 2915
x² + 2x - 2915 = 0
x² + 55x - 53x - 2915 = 0
x(x + 55) - 53(x + 55) = 0.
Therefore, x - 53 = 0
x = 0 + 53 = 53
x + 2 = 53 + 2 = 55
Therefore, the numbers are 53 and 55.
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