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The half-life of polonium-218 s 3.0 min. If you start with 16 mg of polonium-218, how much
time must pass for only 1.0 mg to remain?

Respuesta :

prox222pop

Answer:Fraction remaining = 0.5n where n = # of half lives elapsed

Fraction remaining = 2.0 g/30.0 g = 0.06667

0.06667 = 0.5n

log 0.06667 = n log 0.5

n = 3.907 half lives

3.907 half lives x 3.0 min/half life = 11.7 minutes

Explanation:

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