A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.
A stone is dropped from a bridge and it experiences a uniformly accelerated rectilinear motion. It takes 2.3 s for the stone to reach the water.
We can calculate the height of the bridge, which is equal to the displacement of the stone, using the following kinematic equation.
[tex]s = ut + \frac{1}{2} a t^{2} = (0m/s)(2.3 s) + \frac{1}{2} (9.8m/s^{2} ) (2.3s)^{2} = 26 m[/tex]
where,
- s: displacement
- u: initial speed (0 m/s)
- t: time
- a: acceleration due to gravity (9.8 m/s²)
A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.
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