A child slides down a hill on a toboggan with an acceleration of 1.8m/s .if she starts with an initial push of 1.2n/s how far does she travel in 4.0m/s

Respuesta :

She travels 4.04 m

Further explanation  

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration  

• An equation of uniformly accelerated motion  

V = vo + at  

Vt² = vo² + 2a (x-xo)  

x = distance on t  

vo / vi = initial speed  

vt / vf = speed on t / final speed  

vf=4 m/s

vi=1.2 m/s

a = 1.8 m/s

[tex]\tt vf^2=vo^2+2ax\\\\4^2=1.2^2+2\times 1.8\times x\\\\16=1.44+3.6x\\\\x=4.04~m[/tex]