Answer:
See Explanation
Step-by-step explanation:
[tex] In \: \odot M, \: \overline{MA} \: bisects \: \overline {BC}\\... (given) \\\\
\therefore \overline{MN} \: bisects \: \overline {BC}\\... (\because B-N-C) \\\\
\therefore BN \cong NC... (1)\\\\
In\: \triangle BMN \:\&\:\triangle CMN\\\\
BM\cong CM\\ (radii \: of \: same \: circle) \\\\
MN\cong MN\\ (common \:side) \\\\
BN \cong NC\\ (from\:1)\\\\
\triangle BMN \:\cong\:\triangle CMN\\.. (by\: SSS\: postulate) \\\\
\therefore \angle B\cong \angle C.. (CACT) [/tex]
