Volume (in L) of Carbon dioxide : 23.6 L
Further explanation
Avogadro's hypothesis:
In the same T,P and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
[tex]\tt \dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}[/tex]
Combustion of ethane :
[tex]\tt 2C_2H_6+7O_2\Rightarrow 4CO_2+6H_2O[/tex]
mol ratio of C₂H₆ : CO₂ ⇒ 2 : 4
so the volume of CO₂ :
[tex]\tt \dfrac{V_1}{n_1}=\dfrac{V_2}{n_2}\\\\\dfrac{11.8}{2}=\dfrac{V_2}{4}\\\\V_2=\boxed{\bold{23.6~L}}[/tex]
