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A ball is thrown upward from an initial height of 1.5 m. The ball reaches a height of 5 m then falls to the ground.

What is the total distance traveled by the ball?

What is the displacement of the ball?

Respuesta :

AL2006

Distance:

IF IT WAS TOSSED STRAIGHT UP:

UP: from 1.5m to 5m . . . . . 3.5 m

DOWN: from 5m to the ground ... 5 m

Total distance . . . 8.5 m

Displacement:

IF IT WAS TOSSED STRAIGHT UP:

from 1.5m to the ground.

Displacement = 1.5m down

pristina

Distance is the total path travelled by an object and here, distance travelled by the ball is 11.5 m.

Displacement is the shortest distance between two points and here, the displacement of the ball is -1.5 m.

The answer can be explained as follows:

  • Initially, the ball is at a height of 1.5 m from the ground.

After the throw;

During upward motion of the ball:

  • the maximum height reached by the ball,  [tex]d_1 =5\,m[/tex]

During downward motion of the ball:

  • distance between maximum height and initial position, [tex]d_2=5\,m[/tex]
  • the distance between ground and initial position, [tex]d_3=1.5 m[/tex]
  • So, the total distance travelled by the ball in the downward motion is, [tex]d_2+d_3=1.5\,m+5\,m = 6.5 \,m[/tex].
  • Therefore, the total distance travelled by the ball is, [tex]D = d_1+d_2+d_3= 5\,m+ 6.5 \,m=11.5\,m[/tex].

For calculating displacement;

  • Initial position of the ball, [tex]x_i=1.5\, m[/tex]
  • Final position of the ball,  [tex]x_f=0\,m[/tex]

(Final position is ground, and since all measurements are measured from ground, position of ground is treated as 0 m)

  • Displacement, [tex]\Delta x = x_f -x_i = 0\,m - 1.5\,m = -1.5\, m[/tex]

Learn more about distance and displacement here:

https://brainly.com/question/9054015

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