Answer:
6.711 × 10²⁴ molecules Mg(OH)₂
General Formulas and Concepts:
Chemistry - Atomic Structure
Explanation:
Step 1: Define
650.0 g Mg(OH)₂
Step 2: Define conversions
Avogadro's Number
Molar Mass of Mg - 24.31 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of Mg(OH)₂ - 24.31 + 2(16.00) + 2(1.01) = 58.33 g/mol
Step 3: Convert
[tex]650.0 \ g \ Mg(OH)_2(\frac{1 \ mol \ Mg(OH)_2}{58.33 \ g \ Mg(OH)_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ Mg(OH)_2}{1 \ mol \ Mg(OH)_2} )[/tex]
= 6.71061 × 10²⁴ molecules Mg(OH)₂
Step 4: Check
We are given 4 sig figs. Follow sig fig rules.
6.71061 × 10²⁴ molecules Mg(OH)₂ ≈ 6.711 × 10²⁴ molecules Mg(OH)₂
