Answer:
15.30 ×10²³ molecules of ammonia
Explanation:
Given data:
Volume of ammonia = 57.0 L
Temperature = standard = 273 K
Pressure = standard = 1 atm
Number of molecules of ammonia = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm ×57.0 L = n ×0.0821 atm.L/ mol.K × 273 K
57.0 L.atm = n × 22.41 atm.L/ mol
n = 57.0 L.atm/22.41 atm.L/ mol
n = 2.54 mol
Number of molecules of ammonia:
1 mole of gas have 6.022 ×10²³ molecules of ammonia.
2.54 mol ×6.022 ×10²³ molecules / 1 mol
15.30 ×10²³ molecules
