Answer:
4y + x = 8
Step-by-step explanation:
firstly, we choose any 2 points on the line
point 1 = (0,2)
point 2 = (4,1)
x1 = 0, x2 = 4
y1 = 2, y2 = 1
from,
[tex] \dfrac{y2 - y1}{x2 - x1} = \dfrac{y- y1}{x- x1} [/tex]
[tex] \dfrac{1 - 2}{4 - 0} = \dfrac{y- 2}{x- 0} [/tex]
[tex] \dfrac{ - 1}{4} = \dfrac{y- 2}{x- 0} [/tex]
Cross multiplying,
-1(x) = 4(y - 2)
-x = 4y - 8
4y + x = 8
