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PLZ HELP!! Will mark brainliest !!! Idk how to do this :((

could u answer Part A and B? Part A is pictured Part B is...tan θ = 12/5 and sin θ<0

PLZ HELP Will mark brainliest Idk how to do this could u answer Part A and B Part A is pictured Part B istan θ 125 and sin θlt0 class=

Respuesta :

Answer:

Part A: if cosθ = 4/5 and sinθ < 0, then

secθ = 5/4

sinxθ = 3

tanθ = 15/4, cotθ = 12/5, cscx = 1/3

Step-by-step explanation:

Remember, secθ = 1/4/5 --> 1/4 *5/1 = 5/4

sinx, cscx, cotx, and tanx will be negative because since sinθ < 0 and cosθ is positive, this means that the quadrant will be in quadrant 4

To find these values, we have to use the pythagorean identities

cosx = adj/hyp, sinx = opp/hyp, and tanx = adj/opp

Since 4 is the value of the adjacent side, and we know that x² + 4² = 5².

x² + 16 = 25 ---> x² = 9--> x =3.

Since the value of the opposite side equals 3, and sinx = y, y = 3. Now we can find the rest of our trig values.

Remember that cosθ = x and sinθ = y

tanθ = y/x, cotθ = x/y, secθ = 1/x, cscx = 1/y.

So, since cosθ = 4/5 and sinθ = 3,

tanθ = 15/4, cotθ = 12/5, cscx = 1/3