Answer:
123.1L
Explanation:
Given parameters:
Molarity of Cu(NO₃)₂ = 0.650M
Mass of Cu(NO₃)₂ = 15g
Unknown:
Volume of Cu(NO₃)₂ = ?
Solution:
To solve this problem, we have to first find the number of moles of the given mass;
Number of moles of Cu(NO₃)₂ = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of Cu(NO₃)₂ = 63.5 + 2 (14 + 3(16)) = 187.5g/mol
Number of moles of Cu(NO₃)₂ = [tex]\frac{15}{187.5}[/tex] = 0.08 mol
Molarity is given as;
Molarity = [tex]\frac{number of moles }{volume}[/tex]
Volume = [tex]\frac{number of moles }{molarity }[/tex]
Insert the parameters and solve;
Volume = [tex]\frac{0.08}{0.65}[/tex] = 0.12L
Now mL;
1L = 1000mL
0.12L will give 1000 x 0.12 = 123.1L
