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q=m(delta)T Calculate the final temperature reached when 324 J of heat is added to a 22.5g iron bar initially at 20.0 degrees C. The specific heat capacity of iron is 0.45 J/g degrees C.

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jpelezo1

Answer:

T(final) = 52°C

Explanation:

1st, you need to correct your heat flow formula => q = mcΔT.

m = 22.5g

c = 0.45 j/g·°C

ΔT = T(final) - T(initial) = T(final) - 20°C

q = (22.5g)(0.45j/g·°C)((final) - 20°C) = 324j

=> T(final) = [324j/(22.5g)(0.45j/g·°C)] + 20°C = 52°C

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