Plzz help....Calculate the length of the corresponding sides for FGHIJ and ABCDE. You will need to use the distance formula
[tex]d = \sqrt{x2 - x1) {2}^{?} } + (y2 - y1) {2}^{?} [/tex]
for sides that are not purely horizontal of vertical. Show your work in the table. Afterward, confirm your calculations using GeoGebra.

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Answer:

PLATO anwser

Step-by-step explanation:

Side Calculation Using GeoGebra

AB (2-0)2+(4-4)2=2          2

FG (6-7)2+(1-1)2=1                  1

BC (2-2)2+(3-4)2=1           1

GH (6-6)2+(1.5-1)2=0.5          0.5 C

DI (4-2)2+(2-3)2=5         2.24

HI (5-6)2+(2-1.5)2=1.25  1.12

DE    (4-4)2+(0-2)2=2           2

IJ (5-5)2+(3-2)2=1            1

EA       (0-4)2+(4-0)2=4/2         5.66

JK       (7-5)2+(1-3)2=2/2         2.83

The distance between the points have been calculated.

What is the Distance Formula?

The distance formula is used to calculate distance between two points on a coordinate system.

The formula is

[tex]\rm d = \sqrt { (x_2-x_1)^2+(y_2-y_1)^2}[/tex]

The coordinates of ABCD is A(0,4), B(2,4), C(2,3), D(4,2), E(4,0)

The coordinates of FGHI is F(7,1), G(6,1), H(6,1.5), I(5,2), J(5,3)

AB² =  (2-0)²+(4-4)²      

AB =     2

FG² =  (6-7)²+(1-1)²

FG =1                  

BC² =  (2-2)²+(3-4)²=1          

BC = 1

GH² =  (6-6)²+(1.5-1)²=0.5        

GH = 0.5

DI² =  (5-4)²+(2-2)²

DI = 1

HI² =  (5-6)²+(2-1.5)² = 1.25

HI =  1.12

DE² =  (4-4)²+(0-2)²

DE =    2

IJ² =  (5-5)²+(3-2)²

IJ = 1

EA² =  (0-4)²+(4-0)²      

EA = 5.66

JK² =  (7-5)²+(1-3)²    

JK =    2.83

The missing data of the question is

The coordinates of ABCD is A(0,4), B(2,4), C(2,3), D(4,2), E(4,0)

The coordinates of FGHI is F(7,1), G(6,1), H(6,1.5), I(5,2), J(5,3)

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