Consider the following vectors in component form

a = LeftAngleBracket 2, 10 RightAngleBracket. B = LeftAngleBracket negative 5, negative 12 RightAngleBracket. C = a minus b.

NEED HELP ASAP
What is the magnitude and direction angle of vector c?

|c| = 5, θ = 36.9°
|c| = 5, θ = 53.1°
|c| = 25, θ = 16.3°
|c| = 25, θ = 73.7°

Respuesta :

Answer:

D

Step-by-step explanation:

Ver imagen rileygreene47

The magnitude is 25 and the direction angle of vector c is 73.7°. Option D is correct.

Given, a=⟨2,10⟩, b=⟨-5,-14⟩, c=a-b

We need to find what is the magnitude and direction angle of vector c.

What is the magnitude and direction angle?

Given a position vector v=⟨a,b⟩, the magnitude is found by |v|=√a²+b². The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application. For a position vector, the direction is found by tanθ=(ba)⇒θ=[tex]tan^{-1}[/tex](ba).

Now, vector c=⟨7,24⟩|c|=[tex]\sqrt{7^{2} +24^{2} }[/tex]=25angle =tan(θ)=(168)⇒θ=[tex]tan^{-1}[/tex](168)= 73.7°.

Hence, the magnitude is 25 and the direction angle of vector c is 73.7°.

To learn more about the vectors visit: https://brainly.com/question/13322477.

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