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Complete the coordinate proof of the theorem. Given: A B C D is a rectangle. Prove: The diagonals of A B C D are congruent.
Art: A rectangle is graphed on a coordinate plane. The horizontal x-axis and vertical y-axis are solid. The vertex labeled as A lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as B lies on begin ordered pair a comma 0 end ordered pair. The vertex labeled as D lies on begin ordered pair 0 comma b end ordered pair. The vertex C is unlabeled. Diagonals A C and B D are drawn by dotted lines.

The coordinates of rectangle ABCD are A(0, 0), B(a, 0), C( , ), and D(0, b). The length of AC⎯⎯⎯⎯⎯ is equal to . The length of BD⎯⎯⎯⎯⎯ is equal to . The diagonals of the rectangle have the same length. Therefore, AC⎯⎯⎯⎯⎯ is congruent to BD⎯⎯⎯⎯⎯.

Respuesta :

mhanifa

Step-by-step explanation:

Given coordinates of the rectangle ABCD:

  • A(0, 0), B(a, 0), C(x, y), D(0, b)

Lets first find coordinates of C

We can see that A and B are on same line horizontally, so C and D will be on the parallel line

The distance AB and CD are equal also distance AD and BC are equal, therefore

  • AB = a - 0 = a, CD = a
  • AD = b - 0 = b, BC = b

So the coordinates of C are:

  • x = a, y = b

Now the diagonals:

  • AC = √(a-0)² + (b-0)² = √a²+b²
  • BD =√(0-a)² + (b -0)² = √a² + b²

Since AC = BD, we can state they are congruent

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