Answer:
A. 61.82°;
15.64°
B. 33.37°
Step-by-step explanation:
A.
✍️Angle of elevation from 15 ft:
A right triangle is formed. Apply trigonometric ratios formula to find the angle of elevation from 15 ft.
Thus,
Length of the side Opposite to reference angle = 22 + 6 = 28 ft
Adjacent length = 15 ft
Thus, we would have:
[tex] tan(\theta) = \frac{opp}{adjacent} = \frac{28}{15} [/tex]
[tex] tan(\theta) = 1.8667 [/tex]
[tex] \theta = tan^{-1}(1.8667) [/tex]
[tex] \theta = 61.82 [/tex] (2 d.p)
✍️Angle of elevation from 100 ft:
Thus,
Length of the side Opposite to reference angle = 22 + 6 = 28 ft
Adjacent length = 100 ft
Thus, we would have:
[tex] tan(\theta) = \frac{opp}{adjacent} = \frac{28}{100} [/tex]
[tex] tan(\theta) = 0.28 [/tex]
[tex] \theta = tan^{-1}(0.28) [/tex]
[tex] \theta = 15.64 [/tex] (2 d.p)
B.
✍️Distance you'd be from the screen if you lie on the ground and make an angle of elevation of 40° to the top of the screen:
Adjacent length = your distance from the screen = x
Opposite length = 22 + 6 = 28 ft
Angle of elevation = 40°
Tge trigonometric ratios formula to use would be:
[tex] tan(\theta) = \frac{opp}{adjacent} [/tex]
Plug in the values
[tex] tan(40) = \frac{28}{x} [/tex]
Multiply both sides by x
[tex] x*tan(40) = 28 [/tex]
Divide both sides by tan(40)
[tex] x = \frac{28}{tan(40)} [/tex]
[tex] x = 33.37 [/tex] (2 d.p)
