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During a race, a sprinter increases from 5.0 m/s to 7.5 m/s over a period of 1.25s. What is the sprinter’s average acceleration during this period?

Respuesta :

Answer:

[tex]\boxed {\boxed {\sf 2 \ m/s^2}}[/tex]

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

[tex]a=\frac{\Delta v}{t}[/tex]

The time is 1.25 seconds.  The change in velocity is the difference between the initial velocity and the final velocity.

  • [tex]\Delta v=v_f-v_i[/tex]    
  • The final velocity is 7.5 m/s and the initial velocity is 5.0 m/s
  • [tex]\Delta v =7.5 \ m/s-5.0 \ m/s=2.5 \ m/s[/tex]  

[tex]\Delta v= 2.5 \ m/s\\t=1.25 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{2.5 \ m/s}{1.25 \ s}[/tex]

Divide.

[tex]a=2 \ m/s^2[/tex]

The sprinter's average acceleration is 2 meters per second squared.

Answer: 2 m/s^2

Explanation: Hope this helps :)