Taking into account the reaction stoichiometry and the definition of molarity, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.
Reaction stoichiometry
In first place, the balanced reaction is:
H₂SO₄ + 2 NaOH → Na₂SO₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- H₂SO₄: 1 mole
- NaOH: 2 moles
- Na₂SO₄: 1 mole
- H₂O: 2 moles
The molar mass of the compounds is:
- H₂SO₄: 98 g/mole
- NaOH: 40 g/mole
- Na₂SO₄: 142 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- H₂SO₄: 1 mole× 98 g/mole= 98 grams
- NaOH: 2 moles× 40 g/mole= 80 grams
- Na₂SO₄: 1 mole× 142 g/mole= 142 grams
- H₂O: 2 moles× 18 g/mole= 36 grams
Definition of molarity
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]Molarity= \frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
Moles of H₂SO₄ required
The following rule of three can be applied: If by reaction stoichiometry 80 grams of NaOH react with 1 mole of H₂SO₄, 28 grams of NaOH react with how many moles of H₂SO₄?
[tex]moles of H_{2}S O_{4} =\frac{28 grams of NaOHx1 mole ofH_{2}S O_{4} }{80 grams of NaOH}[/tex]
moles of H₂SO₄= 0.35 moles
Volume of H₂SO₄ required
In this case, you know:
- Molarity= 2 M= 2 [tex]\frac{moles}{liter}[/tex]
- amount of moles= 0.35 moles
Replacing in the definition of molarity:
[tex]2 \frac{moles}{liter}= \frac{0.35 moles}{volume}[/tex]
Solving:
2 [tex]\frac{moles}{liter}[/tex] × volume= 0.35 moles
volume= 0.35 moles ÷ 2 [tex]\frac{moles}{liter}[/tex]
volume= 0.175 liters= 175 mL (being 1 L= 1000 mL)
Finally, 175 mL of 2 M H₂SO₄ will react with 28.0 g of NaOH.
Learn more about
the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
molarity:
brainly.com/question/9324116
brainly.com/question/10608366
brainly.com/question/7429224
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