Respuesta :

Compound interest:

[tex]a = p( 1 + \frac{r}{n} ) { }^{nt} [/tex]

a = final amount

p = principal amount

r = rate of interest

t = time

n = no. of compounding periods per year

p = 10000

r = 5% = 5/100 = 0.05

t = 2

n = 1

[tex]a = 10000(1 + \frac{0.05}{1} ) {}^{2 \times 1} [/tex]

[tex]a = 10000(1 + 0.05) {}^{2} [/tex]

[tex]a = 10000(1.05) {}^{2} [/tex]

[tex]a = 10000(1.1025)[/tex]

[tex]a = 11025[/tex]