Respuesta :
Answer:
the last one I think
Step-by-step explanation:

The vertex form of the quadratic equation is:
[tex]g(x) = (x + 1)^2 - 2[/tex]
And the graph can be seen at the end
How to get the vertex form of the quadratic equation?
For a quadratic equation with leading coefficient a, and with vertex (h, k), the vertex form is:
[tex]y = a*(x - h)^2 + k[/tex]
Here we have:
[tex]g(x) = x^2 + 2x - 1[/tex]
First, we need to find the vertex. by using the known formula we get:
[tex]h = -2/(2*1) = -1[/tex]
To get the value of k, we need to evaluate g(x) in x = -1.
[tex]g(-1) = (-1)^2 + 2*-1 - 1 = 1 - 2 - 1 = -2[/tex]
So the vertex is (-1, -2), which means that the vertex form is:
[tex]g(x) = (x + 1)^2 - 2[/tex]
And its graph can be seen below.
If you want to learn more about quadratic equations:
https://brainly.com/question/1214333
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