Hello!
Topic: Dinamic
Value to calculate: Force
First, we have to calculate the aceleration, for that, lets aplicate the formula:
[tex]\boxed{a=\frac{V-Vi}{t} }[/tex]
How the final velocity is in km/h, we have to convert it on m/s, so:
m/s = km/h / 3,6
m/s = 105 / 3,6
m/s = 29,16
Then, lets replace formula according problem information:
[tex]a = \dfrac{29,16m/s-0m/s}{0,934s}[/tex]
[tex]a =31,22\ m/s^{2}[/tex]
Now, how we have the aceleration, lets applicate second law of newton for calculate the force produced:
[tex]\boxed{F=ma}[/tex]
Replace and resolve it:
F = 856 kg * 31,22 m/s^2
F = 26724,32 kg * m/s^2
Then the force is of 26724,32 kg * m/s^2
But how we know an 1 kg * m/s^2 = 1 N
Then the average of the force is of 26724,32 N
(1) The change in momentum of race car is 89880 kg-km/h.
(2) The average force exerted on the car is of 96231.26 N.
Given data:
The mass of race car is, m = 856 kg.
The initial speed of car is, u = 0 km/h.
The final speed of car is, v = 105 km/h.
The time interval is, t = 0.934 s.
1)
The change in the impact due to average force is known as momentum change. The expression for the change in momentum is given as follows,
[tex]\Delta P = m(v-u)[/tex]
Solving as,
[tex]\Delta P = 856 \times (105-0)\\\\\Delta P = 89880 \;\rm kg.km/h[/tex]
Thus, we can conclude that the change in momentum of race car is 89880 kg-km/h.
2)
Now, use the concept of impulse-momentum which says that the impulse is equal to change in momentum. Which means,
[tex]I = \Delta P[/tex]
And impulse is,
[tex]F \times t = \Delta P\\\\F = \dfrac{\Delta P}{t}[/tex]
Solving as,
[tex]F = \dfrac{89880}{0.934}\\\\F = 96231.26 \;\rm N[/tex]
Thus, we can conclude that the average force exerted on the car is of 96231.26 N.
Learn more about the impulse-momentum theorem here:
https://brainly.com/question/14121529
