Answer:
Any force greater than 24.5 N
Explanation:
To find the frictional force is the 1st step. this can be found by multiplying the coefficient of friction and the normal force. normal force can be found by multiplying gravity (we will say 9.8 m/s/s) and the mass which is 10. You then multiply the result by the coefficient of friction which is 0.25 and it leads us to an answer to 24.5 N. This means that if you pull with exactly 24.5 N, the sled wouldnt move. So you need a force greater than 24.5 N and we have our answer.
I hope I helped correct me if im wrong
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
First, we will calculate the normal force (N), which, in a horizontal surface, has the same magnitude and opposite sense as the weight (W) of the sled.
[tex]|N| = |W| = m \times g = 10 kg \times \frac{9.8m}{s^{2} } = 98 N[/tex]
where,
Then, we will calculate the friction force (f) using the following expression.
[tex]f = \mu \times N = 0.25 \times 98 N = 25 N[/tex]
According to Newton's first law of motion, for the sled to move at a constant velocity, the sum of the force exerted (F) on the sled and the friction force (f) must be zero.
[tex]F + f = 0\\F = -f\\F = -25 N\\|F| = 25 N[/tex]
A force of 25 N is necessary to pull a 10 kg sled across a horizontal surface at a constant velocity if the coefficient of kinetic friction between the sled and the ground is 0.25.
You can learn more about friction here: https://brainly.com/question/18754989
