A spring is 17 cm long when it is lying on a table. One end is then attached to a hook and the other end is pulled by a force that increases to 25 N, causing the spring to stretch to a length of 19.2 cm. How much work was required to stretch the spring?

A. 3.13 J
B. 0.552 J
C. 1.67 J
D. 0.276 J

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skydancerd skydancerd · Answer 1 · 2021-10-22T17:29:20+02:00

Answer:

D. 0.276 J

Explanation:

When I solved this, I got 0.275, so I chose the one closest.

To solve:

convert 17 cm and 19.2 cm to 0.17 m and 0.192 m

W(on spring) = 1/2 (0.192 m - 0.17 m)(25N)

= 1/2 (.022 m)(25 N)

= 0.275

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snehashish65 snehashish65 · Answer 2 · 2022-07-18T18:40:17+02:00

D. 0.276 J

Work is force applied over distance.

Examples of work include lifting an object against the Earth's gravitation, driving a car up a hill, and pulling down a captive helium balloon.

Work is a mechanical form of energy.

The standard unit of work is the joule (J), equivalent to a newton - meter (N · m).

According to the question,

W = Fs

Convert 17 cm and 19.2 cm to 0.17 m and 0.192 m

W = [tex]\frac{1}{2}[/tex](0.192 m - 0.17 m)(25N)

=[tex]\frac{1}{2}[/tex] (.022 m)(25 N)

= 0.276 J

Learn more about work here:https://brainly.com/question/18094932

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