Answer:
[tex]x=\frac{13\pm\sqrt{73} }{8}[/tex]
General Formulas and Concepts:
Pre-Algebra
- Order of Operations: BPEMDAS
- Equality Properties
Algebra I
- Standard Form: ax² + bx + c = 0
- Quadratic Formula: [tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
Step-by-step explanation:
Step 1: Define equation
6x² - 13x + 6 = 2x²
Step 2: Rewrite in Standard Form
- Subtract 2x² on both sides: 4x² - 13x + 6 = 0
Step 3: Define
a = 4
b = -13
c = 6
Step 4: Solve for x/roots
- Substitute: [tex]x=\frac{13\pm\sqrt{(-13)^2-4(4)(6)} }{2(4)}[/tex]
- Exponent: [tex]x=\frac{13\pm\sqrt{169-4(4)(6)} }{2(4)}[/tex]
- Multiply: [tex]x=\frac{13\pm\sqrt{169-96} }{8}[/tex]
- Subtract: [tex]x=\frac{13\pm\sqrt{73} }{8}[/tex]
And we have our final answer!
