the length of a rectangle is 5 more than twice the width. if the perimeter of the rectangle is 76 meters, find the dimensions of the rectangle and choose the equation that represents the perimeter:

1. 76=2w+5
2. 76=2w+2(2w+5)
3. 76=w+2w+5
4. 76=2w+(2w+5)

Respuesta :

Answer:

Dimensions: 11 meters by 27 meters

2. [tex]76=2w+2(2w+5)[/tex]

Step-by-step explanation:

Finding Dimensions:

The perimeter of a rectangle can be written as [tex]2l+2w[/tex] where [tex]l[/tex] is the length and [tex]w[/tex] is the width. It is given that the length is 5 more than twice the length of width and the perimeter of the rectangle is 76 meters.

With this information we can write:

Length = [tex]2w+5[/tex]

[tex]2(2w+5)+2w = 76[/tex] (perimeter of the rectangle)

[tex]4w+10+2w=76[/tex]

[tex]6w=66[/tex]

[tex]w=11[/tex]

Length = [tex]2(11)+5[/tex]

Length = [tex]27[/tex]

∴ The dimensions of the rectangle is 11 meters by 27 meters.

Perimeter

Since the length can be written as [tex]2w+5[/tex], the equation that represents the perimeter of the rectangle is [tex]76=2w+2(2w+5)[/tex]