A projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. The projectile strikes the ground after time at horizontal distance from the base of the platform. [Neglect friction.]

Calculate the vertical distance, h, if the projectile's total time of flight is 4.5 seconds. You must show work to earn full credit with the minimum 3 steps:
1. Equation used
2. Substitution with correct units
3. Final answer with correct units

Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is the gravity acceleration.

In the attachment we see a diagram of the movement, as the body is thrown horizontally, its initial vertical speed is zero.

y = y₀ + [tex]v_o_y[/tex] t - ½ g t²

Where y, y₀i are the current and initial heights, respectively, [tex]v_{oy}[/tex] the vertical initial velocity, g the acceleration of gravity and t the time.

0 =y₀ + 0 - ½ g t²

y₀ = ½ g t²

let's calculate

y₀ = ½ 9.8 4.5²

y₀ = 99.2 m

y₀ = h = 99.2 m

This is the initial height of the object when it is thrown.

In conclusion using the projectile launch we can find the height of the horizontally launched body is:

The height is 99.2 m

Learn more here: brainly.com/question/10903823